4m^2-14m-8=0

Solution for 4m^2-14m-8=0 equation:

4m^2-14m-8=0

a = 4; b = -14; c = -8;
Δ = b2-4ac
Δ = -142-4·4·(-8)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-18}{2*4}=\frac{-4}{8}
=-1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+18}{2*4}=\frac{32}{8}
=4
$